# TX Graph Confidentiality

**URL:** <https://forum.grin.mw/t/tx-graph-confidentiality/1260>\
**Category:** Development and Technical Discussion\
**Created:** [November 24, 2018, 11:12pm UTC](https://forum.grin.mw/t/tx-graph-confidentiality/1260 "2018-11-24T23:12:34Z")\
**Posts on this page:** 1\
**Showing post:** 6

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**Author:** ![tromp](https://yyz2.discourse-cdn.com/flex036/user_avatar/forum.grin.mw/tromp/32/22_2.png) [@tromp](https://forum.grin.mw/u/tromp)\
**Post date:** [November 25, 2018, 8:18am UTC](https://forum.grin.mw/t/tx-graph-confidentiality/1260/6 "2018-11-25T08:18:45Z")

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> [@burrrata](#):
>
> _if_ they had a quantum computer that could break the elliptic curve crypto, then they might be able to decrypt some things like tx amounts

No; Pedersen commitments are only computationally binding. A quantum computer could open any output to any amount they like. But they cannot know the commited amount.

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